Given
g
(
2
)
=
−
8
\displaystyle {g{{\left({2}\right)}}}=-{8}
g
(
2
)
=
−
8
, g'(2) = -5, and
f
(
x
)
=
3
g
(
x
)
\displaystyle {f{{\left({x}\right)}}}=\frac{{3}}{{g{{\left({x}\right)}}}}
f
(
x
)
=
g
(
x
)
3
, find
f
′
(
2
)
\displaystyle {f}'{\left({2}\right)}
f
′
(
2
)
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\displaystyle
Enter your answer as a reduced fraction (like 5/3, not 10/6) or as an integer (like 4 or -2)
Do not enter mixed numbers
Enter DNE for Does Not Exist, oo for Infinity