The amounts of nicotine in a certain brand of cigarette are normally distributed with a mean of 0.973 g and a standard deviation of 0.285 g. The company that produces these cigarettes claims that it has now reduced the amount of nicotine. The supporting evidence consists of a sample of 49 cigarettes with a mean nicotine amount of 0.92 g. Assuming that the given mean and standard deviation have NOT changed, find the probability of randomly selecting 49 cigarettes with a mean of 0.92 g or less.
P(X\displaystyle \overline{{X}} < 0.92 g) = Round to 4 decimal places. NOTE: Answers obtained using exact z-scores or z-scores rounded to 2 decimal places are accepted.