You wish to test the following claim () at a significance level of . denotes the mean of the difference between pre-test and post-test scores.
You believe the population of difference scores is normally distributed, but you do not know the standard deviation. You obtain the following sample of data:
post-test | pre-test |
---|---|
60.1 | 79.3 |
53.7 | 58.1 |
26.8 | 30.8 |
38.5 | 34.4 |
30.8 | 49.6 |
61.1 | 93.2 |
25.7 | 29.7 |
31.7 | 37.2 |
30.8 | 33.5 |
35.4 | 47.4 |
29.4 | 29.9 |
17.9 | 33.7 |
44.2 | 39.5 |
56.2 | 76.3 |
44.2 | 56.5 |
39.6 | 36.6 |
53.2 | 69.4 |
41.1 | 47 |
52.6 | 93.3 |
46.6 | 42.5 |
31.3 | 44 |
In StatCrunch:
- Select Data --> Load data --> From paste
- Paste the data above into the white space with the column titled included
- Select Load Data
- Select Stat --> T Statistics --> Paired
- Choose the appropriate column for Sample 1 and 2 so that you are estimating the improved post-test score:
- Choose the appropriate alternative hypothesis
- Select Compute!
- What is the test statistic for this sample?
test statistic = Round to 3 decimal places. - What is the p-value for this sample? Round to 4 decimal places.
p-value = - The p-value is...
- This test statistic leads to a decision to...
- As such, the final conclusion is that...