16034=3800(1−(1.05)−n)120\displaystyle {16034}=\frac{{{3800}{\left({1}-{\left({1.05}\right)}^{{-{{n}}}}\right)}}}{{\frac{{1}}{{20}}}}16034=2013800(1−(1.05)−n)
n=\displaystyle {n}=n=
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