Given
f
(
x
)
=
4
x
+
6
\displaystyle {f{{\left({x}\right)}}}={4}\sqrt{{{x}}}+{6}
f
(
x
)
=
4
x
+
6
, solve
f
(
x
)
=
9
\displaystyle {f{{\left({x}\right)}}}={9}
f
(
x
)
=
9
.
x
=
\displaystyle {x}=
x
=
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Question 6
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\displaystyle