Suppose that f(x)=x2−13x+42x2−3x−18\displaystyle {f{{\left({x}\right)}}}=\frac{{{x}^{{2}}-{13}{x}+{42}}}{{{x}^{{2}}-{3}{x}-{18}}}. Compute each the following limit. Use exact values.

  1. lim⁡x→−∞f(x)\displaystyle \lim_{{{x}\to-\infty}}{f{{\left({x}\right)}}} =  


  2. lim⁡x→6−f(x)\displaystyle \lim_{{{x}\to{6}^{{-}}}}{f{{\left({x}\right)}}} =  
  3. lim⁡x→6+f(x)\displaystyle \lim_{{{x}\to{6}^{+}}}{f{{\left({x}\right)}}} =  
  4. lim⁡x→6f(x)\displaystyle \lim_{{{x}\to{6}}}{f{{\left({x}\right)}}} =  


  5. lim⁡x→7−f(x)\displaystyle \lim_{{{x}\to{7}^{{-}}}}{f{{\left({x}\right)}}} =  
  6. lim⁡x→7+f(x)\displaystyle \lim_{{{x}\to{7}^{+}}}{f{{\left({x}\right)}}} =  
  7. lim⁡x→7f(x)\displaystyle \lim_{{{x}\to{7}}}{f{{\left({x}\right)}}} =  


  8. lim⁡x→−5−f(x)\displaystyle \lim_{{{x}\to-{5}^{{-}}}}{f{{\left({x}\right)}}} =  
  9. lim⁡x→−5+f(x)\displaystyle \lim_{{{x}\to-{5}^{+}}}{f{{\left({x}\right)}}} =  
  10. lim⁡x→−5f(x)\displaystyle \lim_{{{x}\to-{5}}}{f{{\left({x}\right)}}} =  


  11. lim⁡x→−3−f(x)\displaystyle \lim_{{{x}\to-{3}^{{-}}}}{f{{\left({x}\right)}}} =  
  12. lim⁡x→−3+f(x)\displaystyle \lim_{{{x}\to-{3}^{+}}}{f{{\left({x}\right)}}} =  
  13. lim⁡x→−3f(x)\displaystyle \lim_{{{x}\to-{3}}}{f{{\left({x}\right)}}} =  


  14. lim⁡x→∞f(x)\displaystyle \lim_{{{x}\to\infty}}{f{{\left({x}\right)}}} =  

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