Evaluate the given limit. (Hint: The difference of cubes theorem states that
$\displaystyle {A}^{{3}}-{B}^{{3}}={\left({A}-{B}\right)}{\left({A}^{{2}}+{A}{B}+{B}^{{2}}\right)}$)



$\displaystyle \lim_{{{b}\rightarrow{1}}}{\frac{{{b}^{{3}}-{1}}}{{{b}^{{2}}-{1}}}}$

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