Given that
f ( x ) = x 2 − 9 x \displaystyle {f{{\left({x}\right)}}}={x}^{{2}}-{9}{x} f ( x ) = x 2 − 9 x and
g ( x ) = x + 9 \displaystyle {g{{\left({x}\right)}}}={x}+{9} g ( x ) = x + 9 , find
(a)
f + g \displaystyle {f}+{g} f + g =
Preview Question 6 Part 1 of 11 and its domain is
(
,
)
(b)
f − g \displaystyle {f}-{g} f − g =
Preview Question 6 Part 4 of 11 and its domain is
(
,
)
(c)
f g \displaystyle {f}{g} f g =
Preview Question 6 Part 7 of 11 and its domain is
(
,
)
(d)
f g \displaystyle \frac{{f}}{{g}} g f =
Preview Question 6 Part 10 of 11 and its domain is
{
x \displaystyle {x} x |
x ≠ \displaystyle {x}\ne x = Preview Question 6 Part 11 of 11 }
Note: If needed enter
∞ \displaystyle \infty ∞ as
infinity
and
− ∞ \displaystyle -\infty − ∞ as
-infinity .
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