Use polynomial long division to divide $\displaystyle {4}{x}^{{3}}+{4}{x}^{{2}}-{2}{x}+{1}$ by $\displaystyle {x}-{3}$.

	$\displaystyle -{(}$ $\displaystyle {)}$
		$\displaystyle -{(}$ $\displaystyle {)}$
			$\displaystyle -{(}$ $\displaystyle {)}$

Rewrite $\displaystyle {4}{x}^{{3}}+{4}{x}^{{2}}-{2}{x}+{1}$ in the form $\displaystyle {q}{\left({x}\right)}\times{d}{\left({x}\right)}+{r}{\left({x}\right)}$.

$\displaystyle {4}{x}^{{3}}+{4}{x}^{{2}}-{2}{x}+{1}=$ $\displaystyle \times$ $\displaystyle +$