Compute the given indefinite integral.
∫
(
x
+
6
)
(
x
−
3
)
d
x
=
\displaystyle \int{\left({x}+{6}\right)}{\left({x}-{3}\right)}{\left.{d}{x}\right.}=
∫
(
x
+
6
)
(
x
−
3
)
d
x
=
+
C
\displaystyle +{C}
+
C
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