If
4
x
2
+
4
x
+
x
y
=
16
\displaystyle {4}{x}^{{2}}+{4}{x}+{x}{y}={16}
4
x
2
+
4
x
+
x
y
=
16
and
y
(
4
)
=
−
16
\displaystyle {y}{\left({4}\right)}=-{16}
y
(
4
)
=
−
16
, find
y
′
(
4
)
\displaystyle {y}'{\left({4}\right)}
y
′
(
4
)
by implicit differentiation. Enter exact values.
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