If
x
2
64
+
y
2
25
=
1
\displaystyle {\frac{{{x}^{{2}}}}{{{64}}}}+{\frac{{{y}^{{2}}}}{{{25}}}}={1}
64
x
2
+
25
y
2
=
1
and
y
(
2
)
=
5
15
4
\displaystyle {y}{\left({2}\right)}=\frac{{{5}\sqrt{{{15}}}}}{{4}}
y
(
2
)
=
4
5
15
, find
y
′
(
2
)
\displaystyle {y}'{\left({2}\right)}
y
′
(
2
)
by implicit differentiation. Use exact values.
y
′
(
2
)
\displaystyle {y}'{\left({2}\right)}
y
′
(
2
)
=
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Enter DNE for Does Not Exist, oo for Infinity