The point (1,3) is on the graph of

x2y3+5x2\displaystyle {x}^{{2}}{y}^{{3}}+{5}{x}^{{2}} = y2+23\displaystyle {y}^{{2}}+{23}.

Find the slope of the line tangent to the graph at that point:

dydx\displaystyle \frac{{\left.{d}{y}\right.}}{{\left.{d}{x}\right.}} =



Enter your answer as a whole number (like -4, 0, or 253)

or as a fraction (like 3/5, -7/2, or 1/3)

or as DNE for Does Not Exist or undefined.