Compute the given integral.
∫
1
x
2
+
9
d
x
=
\displaystyle \int{\frac{{{1}}}{{{x}^{{2}}+{9}}}}{\left.{d}{x}\right.}=
∫
x
2
+
9
1
d
x
=
+
C
\displaystyle +{C}
+
C
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