Compute the given integral.
∫
(
12
x
+
5
)
(
6
x
2
+
5
x
+
1
)
28
d
x
=
\displaystyle \int{\left({12}{x}+{5}\right)}{\left({6}{x}^{{2}}+{5}{x}+{1}\right)}^{{28}}{\left.{d}{x}\right.}=
∫
(
12
x
+
5
)
(
6
x
2
+
5
x
+
1
)
28
d
x
=
+
C
\displaystyle +{C}
+
C
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