Compute the given integral.
∫
(
12
x
+
1
)
(
6
x
2
+
x
−
2
)
8
d
x
=
\displaystyle \int{\left({12}{x}+{1}\right)}{\left({6}{x}^{{2}}+{x}-{2}\right)}^{{8}}{\left.{d}{x}\right.}=
∫
(
12
x
+
1
)
(
6
x
2
+
x
−
2
)
8
d
x
=
+
C
\displaystyle +{C}
+
C
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