Solve for the exact solutions in the interval [0,2π)\displaystyle {\left[{0},{2}\pi\right)}[0,2π). If the equation has no solutions, respond with DNE.
12tan2(x)=1−sec(x)\displaystyle \frac{{1}}{{2}}{{\tan}^{{2}}{\left({x}\right)}}={1}-{\sec{{\left({x}\right)}}}21tan2(x)=1−sec(x)
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