Compute the given integral.
∫
(
10
x
−
1
)
e
5
x
2
−
x
d
x
=
\displaystyle \int{\left({10}{x}-{1}\right)}{e}^{{{5}{x}^{{2}}-{x}}}{\left.{d}{x}\right.}=
∫
(
10
x
−
1
)
e
5
x
2
−
x
d
x
=
+
C
\displaystyle +{C}
+
C
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