If
f
(
x
)
=
5
−
4
x
−
6
5
−
9
x
−
3
\displaystyle {f{{\left({x}\right)}}}=\frac{{5}^{{-{4}{x}-{6}}}}{{5}^{{-{9}{x}-{3}}}}
f
(
x
)
=
5
−
9
x
−
3
5
−
4
x
−
6
, find
f
′
(
x
)
\displaystyle {f}'{\left({x}\right)}
f
′
(
x
)
. Use exact values.
f
′
(
x
)
=
\displaystyle {f}'{\left({x}\right)}=
f
′
(
x
)
=
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