If
f
(
y
)
=
log
4
(
csc
(
y
)
)
\displaystyle {f{{\left({y}\right)}}}={{\log}_{{4}}{\left({\csc{{\left({y}\right)}}}\right)}}
f
(
y
)
=
lo
g
4
(
csc
(
y
)
)
, find
f
′
(
y
)
\displaystyle {f}'{\left({y}\right)}
f
′
(
y
)
. Use exact values.
f
′
(
y
)
=
\displaystyle {f}'{\left({y}\right)}=
f
′
(
y
)
=
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