Evaluate the definite integral. Enter exact values.

0122sin1(x)1x2dx=\displaystyle {\int_{{0}}^{{\frac{{1}}{{2}}}}}{\frac{{{2}{{\sin}^{{-{{1}}}}{\left({x}\right)}}}}{{\sqrt{{{1}-{x}^{{2}}}}}}}{\left.{d}{x}\right.}=