Evaluate the given integral. Use exact values.
∫
2
x
−
17
(
x
−
4
)
(
x
−
1
)
d
x
=
\displaystyle \int\frac{{{2}{x}-{17}}}{{{\left({x}-{4}\right)}{\left({x}-{1}\right)}}}{\left.{d}{x}\right.}=
∫
(
x
−
4
)
(
x
−
1
)
2
x
−
17
d
x
=
+
C
\displaystyle +{C}
+
C
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