Simplify:

$\displaystyle \frac{{{x}^{{3}}+{125}}}{{{3}{x}^{{2}}-{16}{x}+{5}}}\cdot\frac{{{x}^{{2}}-{10}{x}+{25}}}{{{4}{x}^{{2}}-{20}{x}+{100}}}\div\frac{{{x}^{{2}}-{25}}}{{{4}{x}-{8}}}$

Enter the numerator and denominator separately into each box below.



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