Is
r
(
t
)
\displaystyle {r}{\left({t}\right)}
r
(
t
)
represented in the list of ordered pairs below a function?
r
(
t
)
=
{
(
−
4
,
6
)
,
(
−
3
,
−
9
)
,
(
−
2
,
−
3
)
,
(
0
,
−
8
)
,
(
0
,
−
10
)
,
(
1
,
−
4
)
}
\displaystyle {r}{\left({t}\right)}={\left\lbrace{\left(-{4},{6}\right)},{\left(-{3},-{9}\right)},{\left(-{2},-{3}\right)},{\left({0},-{8}\right)},{\left({0},-{10}\right)},{\left({1},-{4}\right)}\right\rbrace}
r
(
t
)
=
{
(
−
4
,
6
)
,
(
−
3
,
−
9
)
,
(
−
2
,
−
3
)
,
(
0
,
−
8
)
,
(
0
,
−
10
)
,
(
1
,
−
4
)
}
r
(
t
)
\displaystyle {r}{\left({t}\right)}
r
(
t
)
is a function
r
(
t
)
\displaystyle {r}{\left({t}\right)}
r
(
t
)
is not a function
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