Given the function
f
(
x
)
=
\displaystyle {f{{\left({x}\right)}}}=
f
(
x
)
=
5
x
+
7
\displaystyle {5}{x}+{7}
5
x
+
7
(a) find and simplify
f
(
x
+
3
)
\displaystyle {f{{\left({x}+{3}\right)}}}
f
(
x
+
3
)
5
x
+
22
\displaystyle {5}{x}+{22}
5
x
+
22
5
x
+
10
\displaystyle {5}{x}+{10}
5
x
+
10
5
x
+
4
\displaystyle {5}{x}+{4}
5
x
+
4
5
x
+
36
\displaystyle {5}{x}+{36}
5
x
+
36
5
x
+
29
\displaystyle {5}{x}+{29}
5
x
+
29
(b) find and simplify
f
(
x
)
+
3
\displaystyle {f{{\left({x}\right)}}}+{3}
f
(
x
)
+
3
5
x
+
22
\displaystyle {5}{x}+{22}
5
x
+
22
5
x
+
10
\displaystyle {5}{x}+{10}
5
x
+
10
5
x
+
4
\displaystyle {5}{x}+{4}
5
x
+
4
5
x
+
36
\displaystyle {5}{x}+{36}
5
x
+
36
5
x
+
29
\displaystyle {5}{x}+{29}
5
x
+
29
(c) find and simplify
f
(
x
)
+
f
(
3
)
\displaystyle {f{{\left({x}\right)}}}+{f{{\left({3}\right)}}}
f
(
x
)
+
f
(
3
)
5
x
+
22
\displaystyle {5}{x}+{22}
5
x
+
22
5
x
+
10
\displaystyle {5}{x}+{10}
5
x
+
10
5
x
+
4
\displaystyle {5}{x}+{4}
5
x
+
4
5
x
+
36
\displaystyle {5}{x}+{36}
5
x
+
36
5
x
+
29
\displaystyle {5}{x}+{29}
5
x
+
29
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