Given
f
(
x
)
=
−
2
x
−
5
x
+
1
\displaystyle {f{{\left({x}\right)}}}=\frac{{-{2}{x}-{5}}}{{{x}+{1}}}
f
(
x
)
=
x
+
1
−
2
x
−
5
, evaluate
f
(
−
2
)
\displaystyle {f{{\left(-{2}\right)}}}
f
(
−
2
)
. Round your answer to one decimal place.
f
(
−
2
)
=
1
\displaystyle {f{{\left(-{2}\right)}}}={1}
f
(
−
2
)
=
1
f
(
−
2
)
=
7.5
\displaystyle {f{{\left(-{2}\right)}}}={7.5}
f
(
−
2
)
=
7.5
f
(
−
2
)
=
1.5
\displaystyle {f{{\left(-{2}\right)}}}={1.5}
f
(
−
2
)
=
1.5
f
(
x
)
=
1
\displaystyle {f{{\left({x}\right)}}}={1}
f
(
x
)
=
1
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