Given the function
f
(
x
)
=
{
−
3
x
2
−
3
x
<
−
3
6
x
2
−
6
−
3
≤
x
≤
5
4
x
>
5
\displaystyle {f{{\left({x}\right)}}}={\left\lbrace\begin{array}{cc} -{3}{x}^{{2}}-{3}&{x}<-{3}\\{6}{x}^{{2}}-{6}&-{3}\leq{x}\leq{5}\\{4}&{x}\gt{5}\end{array}\right.}
f
(
x
)
=
⎩
⎨
⎧
−
3
x
2
−
3
6
x
2
−
6
4
x
<
−
3
−
3
≤
x
≤
5
x
>
5
Calculate
f
(
1
)
\displaystyle {f{{\left({1}\right)}}}
f
(
1
)
f
(
1
)
=
−
6
\displaystyle {f{{\left({1}\right)}}}=-{6}
f
(
1
)
=
−
6
f
(
1
)
=
4
\displaystyle {f{{\left({1}\right)}}}={4}
f
(
1
)
=
4
f
(
1
)
=
30
\displaystyle {f{{\left({1}\right)}}}={30}
f
(
1
)
=
30
f
(
1
)
=
−
12
\displaystyle {f{{\left({1}\right)}}}=-{12}
f
(
1
)
=
−
12
f
(
1
)
=
0
\displaystyle {f{{\left({1}\right)}}}={0}
f
(
1
)
=
0
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