Find the horizontal intercept of the equation:
−
12
x
+
1
y
=
20
\displaystyle -{12}{x}+{1}{y}={20}
−
12
x
+
1
y
=
20
(
0
,
20
)
\displaystyle {\left({0},{20}\right)}
(
0
,
20
)
y
=
20
\displaystyle {y}={20}
y
=
20
x
=
20
\displaystyle {x}={20}
x
=
20
y
=
−
5
3
\displaystyle {y}=-\frac{{5}}{{3}}
y
=
−
3
5
x
=
−
5
3
\displaystyle {x}=-\frac{{5}}{{3}}
x
=
−
3
5
(
0
,
−
5
3
)
\displaystyle {\left({0},-\frac{{5}}{{3}}\right)}
(
0
,
−
3
5
)
(
20
,
0
)
\displaystyle {\left({20},{0}\right)}
(
20
,
0
)
(
−
5
3
,
0
)
\displaystyle {\left(-\frac{{5}}{{3}},{0}\right)}
(
−
3
5
,
0
)
Question Help:
Video
Submit
Try a similar question
License
[more..]