Let f(x)=1x−5\displaystyle {f{{\left({x}\right)}}}={\frac{{{1}}}{{{x}-{5}}}} and g(x)=5x+11\displaystyle {g{{\left({x}\right)}}}={5}{x}+{11}.
Then (f∘g)(4)=\displaystyle {\left({f}\circ{g}\right)}{\left({4}\right)}=   ,
(f∘g)(x)=\displaystyle {\left({f}\circ{g}\right)}{\left({x}\right)}=   .

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