If f(x)=x4+6,g(x)=x2,h(x)=x\displaystyle {f{{\left({x}\right)}}}={x}^{{4}}+{6},{g{{\left({x}\right)}}}={x}-{2},{h}{\left({x}\right)}=\sqrt{{{x}}}, then
fgh(x)\displaystyle {f}\circ{g}\circ{h}{\left({x}\right)}=   .

Note: You do not need to multiply out your answer.