Let
f
(
x
)
=
x
+
1
x
+
9
\displaystyle {f{{\left({x}\right)}}}={\frac{{{x}+{1}}}{{{x}+{9}}}}
f
(
x
)
=
x
+
9
x
+
1
f
−
1
(
−
10
)
=
\displaystyle {{f}^{{-{1}}}{\left(-{10}\right)}}=
f
−
1
(
−
10
)
=
Preview
Question 6
Question Help:
Video
Submit
Try a similar question
License
[more..]
\displaystyle
Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)
Enter DNE for Does Not Exist, oo for Infinity