Find the solution of the exponential equation
e
2
x
+
1
=
32
\displaystyle {e}^{{{2}{x}+{1}}}={32}
e
2
x
+
1
=
32
in terms of logarithms, or correct to four decimal places.
x
=
\displaystyle {x}=
x
=
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Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)
Enter DNE for Does Not Exist, oo for Infinity