If ln⁡ a=2\displaystyle {\ln{\ }}{a}={2}, ln⁡ b=3\displaystyle {\ln{\ }}{b}={3}, and ln⁡ c=5\displaystyle {\ln{\ }}{c}={5}, evaluate the following:

(a) ln⁡(a−4b4c4)=\displaystyle {\ln{{\left({\frac{{{a}^{{-{4}}}}}{{{b}^{{{4}}}{c}^{{{4}}}}}}\right)}}}=  

(b) ln⁡b3c4a2=\displaystyle {\ln{\sqrt{{{b}^{{{3}}}{c}^{{{4}}}{a}^{{{2}}}}}}}=  

(c) ln⁡(a−4b4)ln⁡(bc)−4=\displaystyle {\frac{{{\ln{{\left({a}^{{-{4}}}{b}^{{{4}}}\right)}}}}}{{{\ln{{\left({b}{c}\right)}}}^{{-{4}}}}}}=  

(d) (ln⁡ c4)(ln⁡ab3)−3=\displaystyle {\left({\ln{\ }}{c}^{{{4}}}\right)}{\left({\ln{{\frac{{{a}}}{{{b}^{{{3}}}}}}}}\right)}^{{-{3}}}=  

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