Rewrite the expression
logx+5logy3logz\displaystyle {\log{{x}}}+{5}{\log{{y}}}-{3}{\log{{z}}}
as a single logarithm logA\displaystyle {\log{{A}}}. Then the function
A=\displaystyle {A}=  
NOTE: You only need to enter A\displaystyle {A}, not log(A)\displaystyle {\log{{\left({A}\right)}}} so do not type log in your solution.