Find the horizontal asymptote of f(x)=(7x+3)(7x−1)(3−x)(3x+2)\displaystyle {f{{\left({x}\right)}}}=\frac{{{\left({7}{x}+{3}\right)}{\left({7}{x}-{1}\right)}}}{{{\left({3}-{x}\right)}{\left({3}{x}+{2}\right)}}}f(x)=(3−x)(3x+2)(7x+3)(7x−1) y = Preview Question 6
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