Find the horizontal asymptote of
f
(
x
)
=
3
⋅
(
x
+
8
)
(
4
x
−
1
)
(
2
−
x
)
(
3
x
+
2
)
\displaystyle {f{{\left({x}\right)}}}=\frac{{{3}\cdot{\left({x}+{8}\right)}{\left({4}{x}-{1}\right)}}}{{{\left({2}-{x}\right)}{\left({3}{x}+{2}\right)}}}
f
(
x
)
=
(
2
−
x
)
(
3
x
+
2
)
3
⋅
(
x
+
8
)
(
4
x
−
1
)
y =
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