Find the vertical intercept of the equation:
1
x
+
4
y
=
17
\displaystyle {1}{x}+{4}{y}={17}
1
x
+
4
y
=
17
(
17
4
,
0
)
\displaystyle {\left(\frac{{17}}{{4}},{0}\right)}
(
4
17
,
0
)
(
0
,
17
4
)
\displaystyle {\left({0},\frac{{17}}{{4}}\right)}
(
0
,
4
17
)
y
=
17
\displaystyle {y}={17}
y
=
17
(
17
,
0
)
\displaystyle {\left({17},{0}\right)}
(
17
,
0
)
x
=
17
\displaystyle {x}={17}
x
=
17
(
0
,
17
)
\displaystyle {\left({0},{17}\right)}
(
0
,
17
)
x
=
17
4
\displaystyle {x}=\frac{{17}}{{4}}
x
=
4
17
y
=
17
4
\displaystyle {y}=\frac{{17}}{{4}}
y
=
4
17
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