Given the function f(x)=1x−3\displaystyle {f{{\left({x}\right)}}}={\frac{{{1}}}{{{x}-{3}}}}f(x)=x−31 and the function g(x)=2x+3\displaystyle {g{{\left({x}\right)}}}={\frac{{{2}}}{{{x}}}}+{3}g(x)=x2+3 determine g(f(x))\displaystyle {g{{\left({f{{\left({x}\right)}}}\right)}}}g(f(x)). Simplify your answer.
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