Given the function f(x)=3x24x+8\displaystyle {f{{\left({x}\right)}}}={3}{x}^{{2}}-{4}{x}+{8}. Calculate the following values:
f(2)=\displaystyle {f{{\left(-{2}\right)}}}=  
f(1)=\displaystyle {f{{\left(-{1}\right)}}}=  
f(0)=\displaystyle {f{{\left({0}\right)}}}=  
f(1)=\displaystyle {f{{\left({1}\right)}}}=  
f(2)=\displaystyle {f{{\left({2}\right)}}}=