Let
f
(
x
)
=
x
x
−
5
\displaystyle {f{{\left({x}\right)}}}=\frac{{x}}{{{x}-{5}}}
f
(
x
)
=
x
−
5
x
, Evaluate
f
−
1
(
2
)
\displaystyle {{f}^{{-{1}}}{\left({2}\right)}}
f
−
1
(
2
)
.
f
−
1
(
2
)
=
−
0.7
\displaystyle {{f}^{{-{{1}}}}{\left({2}\right)}}=-{0.7}
f
−
1
(
2
)
=
−
0.7
f
−
1
(
10
)
=
2
\displaystyle {{f}^{{-{{1}}}}{\left({10}\right)}}={2}
f
−
1
(
10
)
=
2
f
(
10
)
=
2
\displaystyle {f{{\left({10}\right)}}}={2}
f
(
10
)
=
2
f
−
1
(
2
)
=
10
\displaystyle {{f}^{{-{{1}}}}{\left({2}\right)}}={10}
f
−
1
(
2
)
=
10
f
(
2
)
=
10
\displaystyle {f{{\left({2}\right)}}}={10}
f
(
2
)
=
10
f
−
1
(
2
)
=
−
5
\displaystyle {{f}^{{-{{1}}}}{\left({2}\right)}}=-{5}
f
−
1
(
2
)
=
−
5
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