Solve
exactly.
log
2
(
8
x
−
1
)
=
log
2
(
2
x
+
3
)
\displaystyle {{\log}_{{2}}{\left({8}{x}-{1}\right)}}={{\log}_{{2}}{\left({2}{x}+{3}\right)}}
lo
g
2
(
8
x
−
1
)
=
lo
g
2
(
2
x
+
3
)
x
=
\displaystyle {x}=
x
=
Preview
Question 6
Question Help:
Video
Submit
Try a similar question
License
[more..]
\displaystyle
Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)
Enter DNE for Does Not Exist, oo for Infinity
Decimal values are not allowed