Consider the indefinite integral xx2+73 dx\displaystyle \int{x}{\sqrt[{{3}}]{{{x}^{{2}}+{7}}}}\ {\left.{d}{x}\right.}:

This can be transformed into a basic integral by letting

u=\displaystyle {u}= and

du=\displaystyle {d}{u}=dx\displaystyle {\left.{d}{x}\right.}

Performing the substitution yields the integral

\displaystyle \intdu\displaystyle {d}{u}