The combustion of propane is given by the following reaction.

$\displaystyle \text{C}_{{3}}\text{H}_{{8}}+{3}\text{O}_{{2}}\to{3}\text{CO}_{{2}}+{4}\text{H}_{{2}}\text{O}$

The enthalpy of reaction is −2202.0 kJ/mol. How much energy (in joules) will be released if 79.25 grams of propane is burned. (Molar mass of propane = 44.11 g/mol). Record your answer in scientific notation using 3 significant figures.