Use part I of the Fundamental Theorem of Calculus to find the derivative of
f(x)=2xt3+23dt\displaystyle {f{{\left({x}\right)}}}={\int_{{-{2}}}^{{{x}}}}\sqrt{{{t}^{{3}}+{2}^{{3}}}}{\left.{d}{t}\right.}

f(x)\displaystyle {f}'{\left({x}\right)} =