Use part I of the Fundamental Theorem of Calculus to find the derivative of f(x)=∫−2xt3+23dt\displaystyle {f{{\left({x}\right)}}}={\int_{{-{2}}}^{{{x}}}}\sqrt{{{t}^{{3}}+{2}^{{3}}}}{\left.{d}{t}\right.}f(x)=∫−2xt3+23dt f′(x)\displaystyle {f}'{\left({x}\right)}f′(x) = Preview Question 6
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