If f(x)=0x(t3+2t2+3) dt\displaystyle {f{{\left({x}\right)}}}={\int_{{0}}^{{x}}}{\left({t}^{{3}}+{2}{t}^{{2}}+{3}\right)}\ {\left.{d}{t}\right.}
then
f(x)=\displaystyle {f}{''}{\left({x}\right)}=