Simplify the following powers of i:
a) $\displaystyle {i}^{{9}}=$
b) $\displaystyle {i}^{{57}}=$
c) $\displaystyle {i}^{{79}}=$
d) $\displaystyle {i}^{{95}}=$
e) $\displaystyle {i}^{{1333}}=$

HINT

$\displaystyle {i}^{{60}}={\left({i}^{{2}}\right)}^{{30}}={\left(-{1}\right)}^{{30}}={1}$ 

$\displaystyle {i}^{{62}}={\left({i}^{{2}}\right)}^{{31}}={\left(-{1}\right)}^{{31}}=-{1}$ 

Can you see the pattern?