Solve for x\displaystyle {x}x. 20036x2+8x−300=436x−100+xx+3\displaystyle \frac{{{200}}}{{{36}{x}^{{2}}+{8}{x}-{300}}}=\frac{{4}}{{{36}{x}-{100}}}+\frac{{x}}{{{x}+{3}}}36x2+8x−300200=36x−1004+x+3x
x=\displaystyle {x}=x= Preview Question 6 (Separate answers by a comma.)
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