Solve for $\displaystyle {x}$ :

$\displaystyle \frac{{{5}{x}}}{{-{6}{x}-{30}}}-\frac{{1}}{{7}}=\frac{{1}}{{{7}{x}-{7}}}$
$\displaystyle {x}=$ Preview Question 6 Part 1 of 2	(in the form $\displaystyle {a}{x}^{{2}}+{b}{x}+{c}={0}$ )
	(type: "x=? is not applicable" if one of the solutions is not applicable)