Use undetermined coefficients to find the particular solution to
y
′
′
−
2
y
′
−
15
y
=
e
x
(
64
+
80
x
)
\displaystyle {y}{''}-{2}{y}'-{15}{y}={e}^{{{x}}}{\left({64}+{80}{x}\right)}
y
′′
−
2
y
′
−
15
y
=
e
x
(
64
+
80
x
)
y
p
(
x
)
\displaystyle {y}_{{p}}{\left({x}\right)}
y
p
(
x
)
=
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