Use undetermined coefficients to find the particular solution to
y
′
′
+
4
y
′
+
3
y
=
e
2
x
(
72
+
91
x
+
15
x
2
)
\displaystyle {y}{''}+{4}{y}'+{3}{y}={e}^{{{2}{x}}}{\left({72}+{91}{x}+{15}{x}^{{2}}\right)}
y
′′
+
4
y
′
+
3
y
=
e
2
x
(
72
+
91
x
+
15
x
2
)
y
p
(
x
)
\displaystyle {y}_{{p}}{\left({x}\right)}
y
p
(
x
)
=
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\displaystyle
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