Given the function f(x)=2x2+6x3\displaystyle {f{{\left({x}\right)}}}={2}{x}^{{2}}+{6}{x}-{3}. Calculate the following values:

f(0)=\displaystyle {f{{\left({0}\right)}}}=  
f(2)=\displaystyle {f{{\left({2}\right)}}}=  
f(2)=\displaystyle {f{{\left(-{2}\right)}}}=  
f(x+1)=\displaystyle {f{{\left({x}+{1}\right)}}}=   (Make sure you simplify your answer.)
f(x)=\displaystyle {f{{\left(-{x}\right)}}}=